Subject: RE: [xsl] Best approach From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Thu, 21 Apr 2005 20:21:54 +0100 |
There's been a lot of discussion on comparing documents on this list a couple of weeks ago. Here's one approach: use the XPath 2.0 expression deep-equal(doc('result1.xml'), doc('result2.xml')) If that doesn't meet your needs, you'll have to explain your needs. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: RahilQ [mailto:qamar_rahil@xxxxxxxxxxx] > Sent: 21 April 2005 19:25 > To: XSL List > Subject: [xsl] Best approach > > Hi > > Im sure theres a fairly straight-forward and obvious approach > available. > So Id like some suggestions. > > I have written loads of .xsl files for transforming some .xml > files. The > result is a set of 2 separate .xml files (output from 2 separate .xsl > files) on which Id like to carry out some comparisons. > > Graphically for example the process is such: > > Step 1 : Model1.xml --> Transf1.xsl --> Result1.xml > > Step 2: Model2.xml --> Transf2.xsl --> Result2.xml > > > My main problem isnt how to compare Result1 and Result2 but > how to start > writing them. In which kind of file? > > - Can I import these two files into one .xsl and work upon them? > or > - Should I and can I write some <?xml-stylesheet > href='Compare.xsl'.....?> in Result1.xml when generating it from > Transf1.xsl ? Then only import Result2.xml in Compare.xsl ? > > Could someone please advise me on the best approach. I need a > solution > that can be as piped as possible as all this will ultimately > form part > of one button on the GUI. > > Thanks > Rahil
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