RE: [xsl] Identify last node in nested nodeset with same name

[Mat Bergman <matbergman@xxxxxxxxx>]

Hi Aron and Mukul,

Thanks for your elegant solutions. I'll use them to
finish my project.

I should have mentioned that my client's requirement
is to not modify the XML they delivered. However, 
this requirement has lead to some serious compromises,
and it's clear that your solutions are the most
elegant. 

-Mat

--- Aron Bock <aronbock@xxxxxxxxxxx> wrote:

> Mat,
> 
> Luckily, there's an easier and more "natural" way to
> do this -- don't write 
> "tags", as you do, but create full-fledged elements.
>  Using this, with 
> recursion, yields a simple approach.
> 
> With this input:
> 
> <data>
> <menu name="link1"/>
> <menu name="link2">
>       <menu name="link2a"/>
>       <menu name="link2b"/>
> </menu>
> </data>
> 
> This transform, using call-template:
> 
> <?xml version="1.0" encoding="iso8859-1"?>
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>     <xsl:output method="xml" indent="yes"/>
>     <xsl:strip-space elements="*"/>
> 
>     <xsl:template match="/data">
>         <xsl:call-template name="write-menu">
>             <xsl:with-param name="items"
> select="menu"/>
>         </xsl:call-template>
> 
>     </xsl:template>
> 
>     <xsl:template name="write-menu">
>         <xsl:param name="items" select="/.."/>
>         <ul>
>             <xsl:for-each select="$items">
>                 <li>
>                     <xsl:value-of select="@name"/>
>                     <xsl:if test="menu">
>                         <xsl:call-template
> name="write-menu">
>                             <xsl:with-param
> name="items" select="menu"/>
>                         </xsl:call-template>
>                     </xsl:if>
>                 </li>
>             </xsl:for-each>
>         </ul>
>     </xsl:template>
> </xsl:stylesheet>
> 
> 
> Produces:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <ul>
>   <li>link1</li>
>   <li>link2<ul>
>       <li>link2a</li>
>       <li>link2b</li>
>     </ul>
>   </li>
> </ul>
> 
> 
> As an aside, if iterating over a set of nodes,
> last() in a test can identify 
> the last node.
> 
> Regards,
> 
> --A
> 
> 
> 
> 
> >From: Mat Bergman <matbergman@xxxxxxxxx>
> >Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >Subject: [xsl] Identify last node in nested nodeset
> with same name
> >Date: Thu, 23 Jun 2005 19:26:19 -0700 (PDT)
> >
> >I am working with XML data that shares the same
> >element name for each node set, for example:
> >
> ><menu name="link1"/>
> ><menu name="link2">
> >      <menu name="link2a"/>
> >      <menu name="link2b"/>
> ></menu>
> >
> >My XSL stylesheet transforms this into an HTML
> >unordered list, like this:
> ><ul>
> ><li>link1</li>
> ><li>link2
> >      <ul>
> >      <li>link2a</li>
> >      <li>link2b</li>
> >      </ul>
> ></li>
> ></ul>
> >
> >I can't figure out how to identify the last
> >second-tier node (in this example "link2b") so that
> >the stylesheet can write the closing </ul> tag for
> the
> >nested list. I thought I would reference it with
> >something like <xsl:if test="/menu/menu[last()]">,
> but
> >my XPath must be incorrect because it fails.
> >
> >I am currently writing the opening <ul> and closing
> ></li> tags for the nested list with this:
> >
> ><xsl:template match="menu">
> ><xsl:if test="count(menu)>0">
> ><xsl:text>&lt;ul&gt;</xsl:text>
> ></xsl:if>
> >
> ><xsl:if test="count(menu)=0">
> ><xsl:text>&lt;/li&gt;</xsl:text>
> ></xsl:if>
> ></xsl:template>
> >
> >If I only knew how to identify the last node in
> >/menu/menu, I could easily write the closing tag.
> >
> >Thanks,
> >
> >-Mat
> 
>
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