Subject: [xsl] Concatenating a nodeset (set of attributes) From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Sat, 8 Oct 2005 15:29:57 +0200 |
Hi all, Using XSLT 1.0 I have a table of contents that is of the following (endtags abreviated): <TOC> <STRUC pos="3" title="sometitle"><STRUC pos="1" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="4" title="Another"></ </ <STRUC pos="2" title="sometitle"><STRUC pos="1" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="2" title="Another"></ </ <STRUC pos="2" title="sometitle"><STRUC pos="3" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="6" title="Another"></ </ </TOC> The depth of the STRUC elements is arbitrary. <TOC> <STRUC pos="2" title="sometitle"><STRUC pos="1" title="Another"></ </ <STRUC pos="2" title="sometitle"><STRUC pos="3" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="1" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="2" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="4" title="Another"></ </ <STRUC pos="3" title="sometitle"><STRUC pos="6" title="Another"></ </ </TOC> When I am at the TOC element, I want to process the top STRUC elements, sorting them in full depth. If I can concatenate all pos attributes, I will be able to do this. As far as I know, I cannot say: <xsl:sort select="concat(.//STRUC/@pos)" date-type="number"/> Is there some other way that I can achieve this? Does the following work? <xsl:sort select=".//STRUC/@pos" data-type="number"/> I have not tried sorting more complicated than on a single element or attribute, so I am a little unsure of the mechanics in this. Another problem is of course where @pos > 10. If I had full control, I could do something like: <xsl:sort select="translate(.//STRUC/@pos,'0','A')" data-type="text"/> Is this workable? If not, is there someway else that I can achieve this? I am doing a lot with the data, besides just sorting them, so it is not so clearcut as an identity transformation sorting each element. I hope help is possible :-) Regards, Ragulf Pickaxe :-)
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