Subject: Re: [xsl] regular expression in replace() From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 18 Oct 2005 13:05:21 +0100 |
> My first alternative was to use replace($sourceStr, > ".", "\.") but it says "\." is an invalid replacement string. You need \\ not \, and you need \. in the second argument (otherwise you'll replace evey letter by \.) so to search for all occurrences of the fixed string $aaa in a string $string and replace them by $bbb you need something like replace($string, replace($aaa,'[.+\[\]\\?$^]','\\$0') $bbb) You may need to include other suntax characters in the inner call to replace so they all get quoted with \ before $aaa is used in the main call to replace(). David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] regular expression in rep, UlyLee | Thread | RE: [xsl] regular expression in rep, UlyLee |
Re: [xsl] regular expression in rep, UlyLee | Date | RE: [xsl] regular expression in rep, UlyLee |
Month |