Subject: [xsl] Re: Transform XML to DXL using XSLT From: "rob Jackson" <robjackson2002@xxxxxxxxx> Date: Fri, 3 Mar 2006 01:18:28 -0800 |
Hi, Thanks Gurus for your help. I am really new to XSL so gets stuck in simple problems. How can I modify the xsl program given by Michael and Florent if the Document A is <eapqp:ItemList> <eapqp:Level>Level 1</eapqp:Level> <eapqp:PartNumber>987654321</eapqp:PartNumber> </eapqp:ItemList> I tried by changing the xslt by <xsl:template match="eapqp:Level"> <item name="Level"><text><xsl:value-of select="."/></item> </xsl:template> But it giving me error as illegal prefix. Please suggest a solution. Cheers, Rob On 3/2/06, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > Now I am stuck with a new problem and I am not able to find > > any solution for it. > > If this is a new problem, then I wonder what problems you've been tackling > until now. This is about as classic a one-to-one transformation as they > come. > > > > I want to use XSLT to transform XML file to DXL (Domino XML) file. Dxl > > file is also a xml file used by Lotus Notes. > > For example what could be the xslt for converting document A > > into document B. > > <xsl:template match="ItemList"> > <documents> > <document> > <xsl:apply-templates/> > </document> > </documents> > </xsl:template> > > <xsl:template match="Level"> > <item name="Level"><text><xsl:value-of select="."/></item> > </xsl:template> > > <xsl:template match="PartNumber"> > <item name="PartNumber"><text><xsl:value-of select="."/></item> > </xsl:template> > > Michael Kay > http://www.saxonica.com/ > > > > > Document A: > > > > <ItemList> > > <Level>Level 1</Level> > > <PartNumber>987654321</PartNumber> > > </ItemList> > > > > Document B: > > > > <documents> > > <document> > > <item name="Level"><text>Level 1</text></item> > > <item name="PartNumber"><text>987654321</text></item> > > </document> > > </documents> > > > > Thanks in advance. > > > > Cheers, > > Rob
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