Subject: Re: [xsl] xsl:sort in reverse doc order From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Fri, 03 Mar 2006 22:15:23 -0500 |
My output should look like
usr3 usr2 usr1
I used the following snippet of code but it doesnt seem to work as expected.
T:\ftemp>type aditya.xml <cc> <mods> <mod> <usr>usr1</usr> ....... </mod> <mod> <usr>usr2</usr> ....... </mod> <mod> <usr>usr3</usr> ....... </mod> </mods> </cc>
T:\ftemp>type aditya.xsl <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/"> <xsl:apply-templates select="/cc/mods"/> </xsl:template>
<xsl:template match="/cc/mods"> <xsl:for-each select="mod/usr"> <xsl:sort select="position()" order="descending" data-type="text"/> <xsl:value-of select="."/> <xsl:text> </xsl:text> </xsl:for-each> </xsl:template>
</xsl:stylesheet> T:\ftemp>xslt aditya.xml aditya.xsl con usr3 usr2 usr1
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