Subject: Re: [xsl] reversing or swapping nested node hierarchy From: Chris Capon <abyss@xxxxxxxxxxx> Date: Mon, 20 Mar 2006 16:06:11 -0500 |
G. Ken Holman wrote: >I hope the code below helps. You don't say what you want done with >attributes, so I didn't do anything with them myself. > >. . . . . . . . . Ken > > Thanks for your reply. My example may have been too simple for what I'm trying to do. I should have specified that <a>, <b>, etc need to be transformed, so a simple node copy would not be enough. What I'm essentially looking for is a way to change the node hierarchy during transformation. So, if my document were: <root> <a name="alpha"> <b tag="beta" /> </a> </root> and my templates were: <template match="a"> <aa> <copy-of select="@name" /> </aa> </template> <template match="b"> <bb> <copy-of select="@tag" /> </bb> </template> would there be a way to produce this output: <doc> <bb tag="beta"> <aa name="alpha"> </bb> </doc> where the node hierarchy a/b has been reversed to become bb/aa ? The optimal solution would leave the "b" template generic so the element could be included under other elements like <a>, <c> and <d> in your example. Thanks, Chris.
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