RE: [xsl] Incremental Numbering

Subject: RE: [xsl] Incremental Numbering
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 10 May 2006 10:22:21 +0200
At 2006-05-10 09:12 +0100, Mark Williams wrote:
There could be a large number of options potentially so I'm keen to
avoid a solution that has to input every possible option.

Absolutely ... that was why I asked for clarification and stated my assumptions for your data. You happened to enumerate each element name in your example.


I think what I need to do is structure the XML returned from html page
so that it groups all options with a value of 1 together.

<options> <option>1</option> <option>0</option> <option>1</option> <option>0</option> </options>

I can then just use count and position.

Indeed ... and you can change your focus to each option and build your table rows quite easily:


<xsl:for-each test="option[.=1]">
   <fo:table-row>
     <fo:table-cell>
       <fo:block>
         <xsl:value-of select="count(preceding-sibling::option[.=1])+1"/>
       </fo:block>
     </fo:table-cell>
     <fo:table-cell>
       <fo:block>1</fo:block>
     </fo:table-cell
   </fo:table-row>
</xsl:for-each>

Sorry to all if I didn't make what I was trying to do clear.

No apology necessary ... we can only help based on the information we are given.


. . . . . . . . . Ken

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