Subject: RE: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic From: "Karen McAdams" <kamcadam@xxxxxxxxx> Date: Wed, 17 May 2006 14:52:54 -0700 |
Dave Pawsons' FAQ covers date processing here for xslt2 http://www.dpawson.co.uk/xsl/rev2/dates.html. Which version and processor are you using? Karen -----Original Message----- From: cknell@xxxxxxxxxx [mailto:cknell@xxxxxxxxxx] Sent: Wednesday, May 17, 2006 2:30 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic Given a parameter, let's call it "today" in the form of this string "20060517", how do I create a variable, let's call it "tMinus1" such that it represents a day earlier than "20060517", that would be "20060516". So long as "$today" isn't the first day of a month, a simple subtraction and followed by a type cast that I don't grasp would do the trick. What I'm looking for is guidance on date arithmetic. Thanks. -- Charles Knell cknell@xxxxxxxxxx - email
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] XSLT 2.0/XPath 2.0 Date arith, cknell | Thread | Re: [xsl] XSLT 2.0/XPath 2.0 Date a, Wendell Piez |
[xsl] XSLT 2.0/XPath 2.0 Date arith, cknell | Date | Re: [xsl] XSLT 2.0/XPath 2.0 Date a, Wendell Piez |
Month |