Subject: [xsl] Re: Sort before paging From: "Giancarlo Rossi" <giancarlo_rossi@xxxxxxxxxx> Date: Sun, 27 Aug 2006 11:33:30 +0200 |
Hi... I'm sorry Is the first time using this list... I need to sorting and paging all the document. You could find the xml here: http://www.lastminutesud.it/test/andata_fco.xml Using the code below I get an error: [italian error] Il foglio di stile non include un elemento documento. Il foglio di stile h vuoto oppure potrebbe essere un documento XML in formato non corretto. [english error] The stylesheet does not iclude a valid element. The stylesheet is empty or it should be a not valid xml document with a correct format. Code ------------------------------------- <xsl:param name="start" select="1"/> <xsl:param name="range" select="5"/> <xsl:template match="/"> <xsl:call-template name="positionfilter"> <xsl:with-param name="sortedlist"> <xsl:for-each select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL ist/Outward[position() >=$start and position() < $start + $range]" > <xsl:sort select="Price/Amount" data-type="number" order="ascending" /> <xsl:copy-of select="."/> </xsl:for-each> </xsl:with-param> </xsl:call-template/> </xsl:template> <xsl:template name="positionfilter"> <xsl:param name="sortedlist"/> <xsl:for-each select="$sortedlist/*[(position() >= $start) and (position() < $start + $range)]"> 'my code </xsl:for-each> </xsl:template> ------------------------------------------------------------
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