Subject: [xsl] Group and display the min value [for each item] From: "Giancarlo Rossi" <giancarlo_rossi@xxxxxxxxxx> Date: Wed, 30 Aug 2006 09:18:19 +0200 |
I'm trying to get the min value from an xml file. This code works but sometimes doesnt take the just min value and most of all not sort the results in a ascending way. Could you help me ? Regards. you could see The xml file in www.lastminutesud.it/test/last_mad_lgw.xlm <xsl:key name="OutwardList" match="Outward" use="SegmentList/Segment/Operator/Name"/> <xsl:template match="/"> <xsl:for-each select="//Outward[generate-id(.)=generate-id(key('OutwardList',SegmentList/S egment/Operator/Name))]"> <xsl:sort select="Price/Amount" order="ascending" data-type="number"/> <xsl:variable name="ok_op" select="SegmentList/Segment/Operator/Name" /> <xsl:variable name="min"> <xsl:for-each select="//Outward[SegmentList/Segment/Operator/Name=$ok_op]/Price/Amount/tex t()"> <xsl:sort select="." order="ascending" data-type="number"/> <xsl:if test="position() = 1"> <xsl:value-of select="."/> </xsl:if> </xsl:for-each> </xsl:variable> <xsl:value-of select="$min"/> </xsl:for-each> </xsl:template>
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