Subject: Re: [xsl] XML Question From: LINKE Markus <markus.linke@xxxxxxxx> Date: Tue, 3 Oct 2006 16:47:02 -0500 (CDT) |
I've tried it but I receive an: SystemID: xxx.xsl Location: 98:0 Description: The URI urn:schemas-microsoft-com:xslt does not identify an external Java class error message at this location: </xsl:variable> <xsl:value-of select="msxsl:node-set($theResult)"/> <!-- here --> </xsl:template> ??? Thanks for your help! Markus ----- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > You need to apply this code: > http://www.topxml.com/code/default.asp?p=3&id=v20010323001030 > > to all leaf nodes in the tree. > > > > -- > Cheers, > Dimitre Novatchev > --------------------------------------- > Truly great madness cannot be achieved without significant > intelligence. > --------------------------------------- > To invent, you need a good imagination and a pile of junk > ------------------------------------- > You've achieved success in your field when you don't know whether > what > you're doing is work or play > > > > On 10/3/06, LINKE Markus <markus.linke@xxxxxxxx> wrote: > > this might be the better audience ... > > > > ----- LINKE Markus <markus.linke@xxxxxxxx> wrote: > > > Hi, > > > > > > I am not sure if this is the right list for such a question, but > lets > > > try :) > > > > > > I would like to create a list of xpaths via xsl from a given > > > xml-structure like this: > > > > > > <a> > > > <b> > > > <c> > > > content > > > </c> > > > <d> > > > morecontent > > > </d> > > > </b> > > > </a> > > > > > > it should show the full xpath like > > > > > > a/b/c ====> content > > > a/b/d ====> morecontent > > > > > > and not just > > > > > > c => content > > > d => morecontent > > > > > > Ideas anyone? I am looking for either a script or some xsl ... > > > > > > Cheers, > > > Markus
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