Subject: SV: [xsl] XML Question From: "Per Osnes" <per.osnes@xxxxxx> Date: Wed, 4 Oct 2006 13:18:13 +0200 |
Hi folks, This template gives the required output (in Altova). <xsl:template match="//*[not(*)]"> <xsl:variable name="path"> <xsl:for-each select="ancestor::*"><xsl:value-of select="name()"/>/</xsl:for-each> <xsl:value-of select="name()"/> </xsl:variable> <xsl:text> </xsl:text> <xsl:value-of select="$path"/> <xsl:value-of select="' ===> '"/> <xsl:value-of select="text()"/> </xsl:template> Actually I wanted to replace the "for each" by something like <xsl:value-of select="string-join(((name(ancestor::*)), name()), '/')"/> but Altova gives error message "too many items"... I have used this method earlier for producing the full path for elements in an XML schema: select="string-join((ancestor::xs:element/@name, ./@name), '.')" Any comments from the experts? - Per Osnes. ----- LINKE Markus <markus.linke@xxxxxxxx> wrote: > Hi, > > I am not sure if this is the right list for such a question, but lets > try :) > > I would like to create a list of xpaths via xsl from a given > xml-structure like this: > > <a> > <b> > <c> > content > </c> > <d> > morecontent > </d> > </b> > </a> > > it should show the full xpath like > > a/b/c ====> content > a/b/d ====> morecontent > > and not just > > c => content > d => morecontent > > Ideas anyone? I am looking for either a script or some xsl ... > > Cheers, > Markus
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