Re: [xsl] Looping a node in XSLT

["Loana Chatelain" <loana.chatelain@xxxxxxxxx>]

Hi,

This is because "for $n in (1 to 10) return ." is an XPath 2.0
expression and can only be used in XSLT 2.0 stylesheets, whereas
you're probably using a XSLT 1.0 processor.

Loana

On 3/6/07, Senthilkumaravelan Krishnanatham <senthil@xxxxxxxxx> wrote:
> I am not using Saxon 8.8 and use java parser to do the same.
> for loop syntax is nt working in there,
>
>
> On Mar 6, 2007, at 5:39 PM, Abel Braaksma wrote:
>
> > Senthilkumaravelan Krishnanatham wrote:
> >>
> >> Compiler warnings:
> >>   line 5: Illegal attribute 'select'.
> >> ERROR:  'Syntax error in 'for 1 to 10 return .'.'
> >> FATAL ERROR:  'Could not compile stylesheet'
> >>
> >> (Location of error unknown)XSLT Error
> >> (javax.xml.transform.TransformerConfigurationException): Could not
> >> compile stylesheet
> >> Is there anyway I could use
> >
> >
> > Yes, there were errors in my template, it's getting a bit late over
> > here, but nothing unusual, just a few typos, easy enough to fix if
> > you follow the syntax error messages. A fix (checked and compiled
> > with Saxon 8.8):
> >
> >    <xsl:template match="products">
> >        <xsl:copy><xsl:apply-templates select="customer" /></xsl:copy>
> >    </xsl:template>
> >    <xsl:template match="customer">
> >        <xsl:copy-of select="for $n in (1 to 10) return ." />
> >    </xsl:template>