Subject: Re: [xsl] Key to select all same nodes(same @id) except current node From: Tech Guru <tech_gr@xxxxxxxxx> Date: Wed, 7 Mar 2007 09:48:52 -0800 (PST) |
Thanks David for your help. I am working on XSLT 1.0. >not sure what you mean by top element. If you mean ancestor then in 2 >that's >key('ParentKey',@id) intersect ancestor::category By saying top element, I mean all ancestors of the current element. Could you please tell me what the above syntax would be in XSLT 1.0. - R ----- Original Message ---- From: David Carlisle <davidc@xxxxxxxxx> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Sent: Wednesday, March 7, 2007 12:40:19 PM Subject: Re: [xsl] Key to select all same nodes(same @id) except current node best to say of you want xslt1 or 2. in 2 key('ParentKey',@id) except . will return all category elements with the current id except the current node. in 1 you'd write it as key('ParentKey',@id)[not(generate-id()=generate-id(current()))] > Also I want to check whether any <category> elements > with same @id, exists in all top elements of current > <category> element. not sure what you mean by top element. If you mean ancestor then in 2 that's key('ParentKey',@id) intersect ancestor::category David _____________________________________________________________________________ _______ We won't tell. Get more on shows you hate to love (and love to hate): Yahoo! TV's Guilty Pleasures list. http://tv.yahoo.com/collections/265
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Key to select all same no, David Carlisle | Thread | Re: [xsl] Key to select all same no, Tech Guru |
Re: [xsl] flatened hiearchies for x, ac | Date | Re: [xsl] Key to select all same no, Tech Guru |
Month |