Re: [xsl] Key to select all same nodes(same @id) except current node

Subject: Re: [xsl] Key to select all same nodes(same @id) except current node
From: Tech Guru <tech_gr@xxxxxxxxx>
Date: Wed, 7 Mar 2007 09:48:52 -0800 (PST)
Thanks David for your help.
I am working on XSLT 1.0.

>not sure what you mean
by top element. If you mean ancestor then in 2
>that's

>key('ParentKey',@id)
intersect ancestor::category

By saying top element, I mean all ancestors of
the current element.
Could you please tell me what the above syntax would be
in XSLT 1.0.

- R
----- Original Message ----
From: David Carlisle
<davidc@xxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Sent: Wednesday, March
7, 2007 12:40:19 PM
Subject: Re: [xsl] Key to select all same nodes(same @id)
except current node


best to say of you want xslt1 or 2.

in 2
key('ParentKey',@id) except .

will return all category elements with the
current id except the current
node.

in 1 you'd write it as
key('ParentKey',@id)[not(generate-id()=generate-id(current()))]

> Also I want
to check whether any <category> elements
> with same @id, exists in all top
elements of current
> <category> element.

not sure what you mean by top
element. If you mean ancestor then in 2
that's


key('ParentKey',@id)
intersect ancestor::category

David
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