Subject: Re: [xsl] how to sort a union using number()? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 15 Mar 2007 23:56:16 GMT |
> Error on line 228 of file:/e:/schema.xsl: > XPTY0004: A sequence of more than one item is not allowed as the first > argument of number() that means that NumberString|$associations/NumberString selected more than one node, in xslt1 the other nodes would have been silently discarded, but in xslt2 its an error. NumberString|$associations/NumberString/number(.) would avoid that, but return a sequence of numbers and again (in xslt2) this is an error. If you just want to sort on the first NumberString descendent of each item you can use [1] to ensure the path just selects one item. There is something strange about your sort key though $associations/NumberString/number(.) starts with a variable, so in particular it does not depend on the item being sorted, so the sort key (from this branch of the union) is a constant value (within this scope). Sorting a list with a constant sort key is a non-op? David
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