Re: [xsl] &

[Marco <spinmar@xxxxxxxxx>]

David Carlisle ha scritto:
> > I have a xml document with:
> >
> >     
> > > ......
> > >       
> > <NODE n="1" url="url1" visible_url="url2?escape&amp;amp;chars"></NODE>
> > ..
> >     
>
> this is almost certainly a mistake in the input and if you have control
> over the generation of these files, you should fix the generator to
> produce
> <NODE n="1" url="url1" visible_url="url2?escape&amp;chars"></NODE>
>   
The problem is that I don't produce the xml but I receive it from an 
external source.
>   
> > and it's ok;
> > the problem is the onmouseover attribute where I get:
> >     
>
> disable-output-escaping is defined to do nothing in attribute values.
> It's almost always a bad idea to use d-o-e in any case.
>
>
>
> you need to replace &amp; by &, in XSLT2, you could use
>
> select="replace(@visible_url,'&amp;amp;',' &amp;')"
>
> in XSLT1 you could use one of the many replace templates posted to this
> list, or the faq to do the same transformation.
>   
For example I can use this one:

<xsl:template name="replaceUrl">
   <xsl:param name="url" />
   <xsl:choose>
       <xsl:when test="contains($url, '&amp;amp;')">
           <xsl:value-of select="concat(substring-before($url, 
'&amp;amp;'), '&amp;')" disable-output-escaping="yes" />
           <xsl:call-template name="replacee">
               <xsl:with-param name="url"><xsl:value-of 
select="substring-after($url, '&amp;amp;')" 
disable-output-escaping="yes"/></xsl:with-param>
           </xsl:call-template>
       </xsl:when>
       <xsl:otherwise>
           <xsl:value-of select="$url" disable-output-escaping="yes" />
       </xsl:otherwise>
   </xsl:choose>
</xsl:template>

For Abel:

my javascript function (ss) on onmouseover shows the url in the status 
bar of browser and I have to use it.
So I'd like to find a method to solve my problem in XSL 1.0.

Best regards

> David