Subject: RE: [xsl] Extract input filename From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx> Date: Thu, 17 May 2007 15:48:55 +0530 |
Well, that probably means you changed the parameter name from "meta" to "data" in one place but not in the other place.
<xsl:param name="meta" as="xs:string" required="yes"/> <xsl:variable name="filename" select="document($meta)" /> <xsl:template match="/"> <doi> <xsl:copy-of select="$filename/doi/text()" /> </doi> </xsl:template>
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