Subject: Re: [xsl] passing parameters to xsl stylesheets From: mozer <xmlizer@xxxxxxxxx> Date: Sun, 20 May 2007 17:06:01 +0200 |
You are passing parameter ! you said to xsltproc that $toto is equal to 'from' And it did what you wanted
In fact, it seems you want more you want to tell to xproc to "use the value 'from' as the name of the element where to get value"
<?xml version="1.0" encoding="ISO-8859-1" ?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="toto" /> <xsl:template match="/note"> <html> <body> <xsl:value-of select="*[local-name()=$toto]" /> </body> </html> </xsl:template> </xsl:stylesheet>
Hi all Will you help me please? I'm trying to pass a parameter to the following xsl stylesheet:
<?xml version="1.0" encoding="ISO-8859-1" ?> - <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="toto" /> - <xsl:template match="/note"> - <html> - <body> <xsl:value-of select="$toto" /> </body> </html> </xsl:template> </xsl:stylesheet>
The xml file which uses the xsl file is simply:
<?xml version="1.0" ?> - <note> <to>Tove</to> <from>Jani</from> </note>
To pass the parameter I use this command: $ xsltproc --stringparam toto 'from' myxslfile.xsl myxmlfile.xml
The result is: <html><body>from</body></html> While I was expecting <html><body>Jani</body></html>
Thank you in advance!! Youness (france)
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