Re: [xsl] XPath MOD 10 calculation

[Abel Braaksma <abel.online@xxxxxxxxx>]

Abel Braaksma wrote:
>    sum(
>        for $i in $x[position() mod 2 = 1] return $i * 3,
>        for $i in $x[position() mod 2 = 0] return $i,
>        = number(substring(., string-length(.) - 1, 1))

I must be sleepy or something. "for $i in $x[position() mod 2 = 0] 
return $i" is the same as " $x[position() mod 2 = 0]" of course ;) and 
that comma should be a right parenthesis:

  sum(
      for $i in $x[position() mod 2 = 1] return $i * 3,
      $x[position() mod 2 = 0])
      = number(substring(., string-length(.) - 1, 1))