Subject: [xsl] grouping-problem From: Annina.Hirschi-Wyss@xxxxxxxxxxxx Date: Thu, 14 Jun 2007 10:59:11 +0200 |
Hi, I'm working with XSLT 2 Saxon 8 And I am a newbie with XSLT... ---- Here is the XML file "stats.xml" <statistic> <class name="CI_Citation" associationName="citation" count="50"> </class> <class name="CI_Citation" associationName="title" count="100"> </class> <class name="MD_Metadata" count="300"> </class> <class name="MD_Metadata" associationName="parentId" count="3"> </class> <class name="CI_Citation" associationName="citation" count="60"> </class> <class name="CI_Citation" associationName="title" count="200"> </class> <class name="MD_Metadata" count="50"> </class> <class name="MD_Metadata" associationName="parentId" count="10"> </class> [...] </statistic> ---- Output should be a csv-textfile like: CI_Citation citation 110 title 300 MD_Metadata 350 parentId 13 ---- I managed quite well, but only did my XSLT not consider the class MD_Metadata without the "associationName": "stats.xsl" <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output encoding="ISO-8859-1"/> <xsl:output method="text"/> <xsl:template match="/"> <xsl:apply-templates select="statistic"/> </xsl:template> [...] <xsl:for-each-group select="class" group-by="@name"> <xsl:value-of select="current-grouping-key()"/> <xsl:for-each-group select="current-group()" group-by="@associationName" > <xsl:text>;</xsl:text> <xsl:value-of select="current-grouping-key()"/> <xsl:text>;</xsl:text> <xsl:value-of select="sum(current-group()/@count)"/> </xsl:for-each-group> </xsl:for-each-group> [...] ---- Is there a possibility to list the class MD_Metadata even if there is no "associationName"? Thanks for your reply!
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