Subject: Re: [xsl] translate to XML using XSL into an HTML table From: Steve <subsume@xxxxxxxxx> Date: Fri, 3 Aug 2007 16:03:23 -0400 |
There's a solution to fill in //LAST and //PHONE with their corresponding //FIRSTs but I'm hard pressed to produce it now, given that your XML <listing /> doesn't encapsulate 1 member but several. If you have control over the XML I'd wrap <member /> around each FIRST, LAST, PHONE pair. Perhaps someone else will chime in. -S On 8/3/07, oryann9 <oryann9@xxxxxxxxx> wrote: > > <xsl:for-each select="//LISTING"> should match both > > listings (...I believe). > > Can you post some idea of your output HTML? > > I'm guessing <tr><td>first</td><td>last</td></tr> > > My Phone Book > ------------------ > FIRST|LAST|PHONE > ------------------ > Derek| > Steve| > Corey| > Tiko | > Kurt | > Jane | > ------------------ > > is from > > <?xml version="1.0"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="html"/> > <xsl:template match="/"> > <html> > <head> > <title> My Phone Book</title> > </head> > <h2> My Phone Book </h2> > <body bgcolor="YELLOW"> > <table border="3"> > <tr bgcolor="lightblue"> > <th>FirstName</th> > <th>LastName</th> > <th>Phone</th> > </tr> > <xsl:for-each select="//FIRST"> > <tr> > <td><xsl:value-of select="."/></td> > </tr> > </xsl:for-each> > </table> > </body> > </html> > </xsl:template> > </xsl:stylesheet> > > > > ____________________________________________________________________________________Ready for the edge of your seat? > Check out tonight's top picks on Yahoo! TV. > http://tv.yahoo.com/
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