Subject: Re: [xsl] Re: Format Number and Empy Elements From: Florent Georges <darkman_spam@xxxxxxxx> Date: Wed, 8 Aug 2007 18:46:38 +0200 (CEST) |
Mark Anderson wrote: Hi > Strangely, sum(value[.]) still gave NaN for Element A The predicate [.] will always be true, as an existing node is converted to true (meaning "yes, I exist"). This is not the same for [string(.)] however. Regards, --drkm _____________________________________________________________________________ Ne gardez plus qu'une seule adresse mail ! Copiez vos mails vers Yahoo! Mail
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