Subject: Re: [xsl] how to select elements based on optional container argument From: "Nick Shepherd" <nick@xxxxxxxxxxxxxxxx> Date: Tue, 21 Aug 2007 18:10:55 -0400 |
the following isn't tested and there may be a more elegant solution but this is probably how I would handle a situation like this: <xsl:apply-templates match="container"> <xsl:choose> <xsl:when test="@select > 0"> <xsl:for-each select="item"> <xsl:comment>Same dirty Business</xsl:comment> </xsl:for-each> </xsl:when> <xsl:otherwise> <xsl:for-each select="item"> <xsl:if test="position() <= @select"> <xsl:comment>Do your dirty business here</xsl:comment> </xsl:if> </xsl:for-each> </xsl:otherwise> </xsl:choose> </xsl:apply-templates> hope that helps :) Nick On 8/21/07, Andreas Kemkes <a5sk4s@xxxxxxxxx> wrote: > XSLT 1.0 is a constraint. > > I'm having trouble with a select expression to select the marked elements (<!--X-->) in the following XML: > > <container select="2"> > <item>...</item><!--X--> > <item>...</item><!--X--> > > <item>...</item> > > </container> > <container> > > <item>...</item><!--X--> > > <item>...</item><!--X--> > > > <item>...</item><!--X--> > > > </container> > > <container select="1"> > > <item>...</item><!--X--> > <item>...</item> > > <item>...</item> > > <item>...</item> > > </container> > > In the case of a no select attribute all items in the container should be in the node set. > If there is a attribute select="n", only the first "n" items should be in the node set. > The expression needs to work across all containers. > > There is the additional constraint that only items with parent container are to be selected. > > > Where could I start to look for code examples that solves a similar problem? > > Thanks in advance for your help. > > > > > ____________________________________________________________________________________ > Shape Yahoo! in your own image. Join our Network Research Panel today! http://surveylink.yahoo.com/gmrs/yahoo_panel_invite.asp?a=7
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