Subject: RE: [xsl] how to get xml file name in xsl From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 16 Oct 2007 13:55:35 +0100 |
In XSLT 1.0 the answer is no. The usual remedy is to pass it in to the transformation as a parameter. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Vankadaru.Gupta@xxxxxxxxxxxxxxxxxx > [mailto:Vankadaru.Gupta@xxxxxxxxxxxxxxxxxx] > Sent: 16 October 2007 13:44 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] how to get xml file name in xsl > > Hi, > > Is it possible in XSL to get the file name of the XML > document it is currently processing? > > I am using MSXML and the tag "document-uri(/)" does not work for me. > > Can anybody please help me out? > > > > Thanks > > Nagesh Gupta V > > > > DISCLAIMER: > This message contains privileged and confidential information > and is intended only for an individual named. If you are not > the intended recipient, you should not disseminate, > distribute, store, print, copy or deliver this message. > Please notify the sender immediately by e-mail if you have > received this e-mail by mistake and delete this e-mail from > your system. E-mail transmission cannot be guaranteed to be > secure or error-free as information could be intercepted, > corrupted, lost, destroyed, arrive late or incomplete or > contain viruses. The sender, therefore, does not accept > liability for any errors or omissions in the contents of this > message which arise as a result of e-mail transmission. If > verification is required, please request a hard-copy version.
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