Accessing current node attributes

[George Phillips <phillips@xxxxxxxxxxxx>]

I'd like to write an XSL style sheet that reduces well-formed HTML
down to a simple list of links.  Something like this nearly
sufficies:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl";>
  <xsl:template match="a[attribute(href)]">
    <A HREF="{.[attribute(href)]}">
    <xsl:value-of expr="." />
    </A>
  </xsl:template>
</xsl:stylesheet>

But "{.[attribute(href)]}" doesn't get me the HREF attribute of the
current A node being processed.  Not that I expect it to as it is
not XSL-grammatically correct.  In fact, I can't see any way to do
this in XSL at all.  Am I missing something or is this really not
possible?

			-- George


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list