Subject: RE: Need XML output with <!DOCTYPE ... , HOW to do that ? From: "White, David" <David.White@xxxxxx> Date: Tue, 21 Sep 1999 15:26:53 +0200 |
> Hi there, > > I just need the following XML result from a XSL processing : > > <!DOCTYPE root PUBLIC "imediation/protocol" "protocol.dtd"> > <root> > &protocol; > </root> > > What's the Style Sheet needed to obtain such result ? Ahh, this. Since you are using XT, I can say that the following: <xsl:template match="/"> <xsl:processing-instruction name='xml'>version="1.0"</xsl:processing-instruction> <xsl:text disable-output-escaping="yes"><![CDATA[ <!DOCTYPE wml PUBLIC "-//WAPFORUM//DTD WML 1.1//EN" "http://www.wapforum.org/DTD/wml_1.1.xml">]]> </xsl:text><wml> <xsl:apply-templates/> </wml> </xsl:template> works, in that it produces: <?xml version="1.0"?> <!DOCTYPE wml PUBLIC "-//WAPFORUM//DTD WML 1.1//EN" "http://www.wapforum.org/DTD/wml_1.1.xml"> <wml> [stuff] </wml> Horrible, isn't it? I hope the next version of XT supports xsl:output. I find the above extremely inelegant. Dave XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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