xsl: how to select slice of tree regarding the node position

[pietro abate <pietro.abate@xxxxxx>]

Hi,
I've a tree like

 |---B
 |---B |---D
 |---C-|---D
A|---B    (1)
 |---C-|---D

and I would like to trasform in a tree like
       |---B
 |---H-|---B
 |
 |---H-|---newC
 |
 |     |---D
A|---H-|---D
 |     |---newC
 |
 |---H-|---B
 |
 |---H-|---newC
 |
 |---H-|---D
       |---newC
In other words I want ot group the B, and split the C, but in accord
with the position in the original tree;
So I don't know how to select, for example, the B(1) because it's a B
and because it's between two C.If I try to make a template to select
all the B I lose the information about the position, an if I try to
select all the C I lose the possibility of group _all_ the previous B.
I succeded with a little recursive perl (XML::DOM) program, but I would
like to do this in xsl.

Suggestion ?

pietro


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