Subject: Re: Accessing the element stack generically From: "Clark C. Evans" <clark.evans@xxxxxxxxxxxxxxxxxxxx> Date: Fri, 15 Oct 1999 13:22:22 -0400 (EDT) |
On Fri, 15 Oct 1999, Steve Muench wrote: > These should be exactly the elements on the > ancestor-or-self axis so a select="ancesor-or-self::*" > should return the node list of elements > including yourself in the "stack" (in reverse document order) Yep. Found it, thanks! XT returns the list in document order, and the specification states that lacking a sort clause, the for-each construct always returns things in document order... thus,the solution is portable! I'm thrilled. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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