Absolute-path/index challenge

[Thomas E Enebo <Thomas.E.Enebo-2@xxxxxxxxxx>]

As an extension of the position() of parent question from digest 480,
I have a challenge.  How can a template be created, such that it will 
print out the complete path of current node from the root?  As an
example:

<A>
  <B>
    <C/>
  </B>
  <B>
    <C/>
    <C/> <--- calling a template with current() here...
  </B>
  <B>
  </B>
</A>

will yield

A:1.B:2.C:2

Where the first part is the element name and the second part is it's
relative position with respect to all other nodes at the same level.

I know I would need to create a named template that recurses passing
the parent to next invocation of template.  I also know the end case
is when the current node is the root.    

To print the index I think I would use David Carlisles comment on
position
thread yesterday..

  <xsl:value-of select="1+count(../preceding-sibling::*)"/>

Anyone?

-Tom

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