Subject: RE: multiple input files to one output file From: James Garriss <jgarriss@xxxxxxxxx> Date: Fri, 04 Feb 2000 12:34:30 -0500 |
// Set a param named "userdirectory", that the stylesheet can obtain. processor.setStylesheetParam("userdirectory", "'" + userDirectoryURL + "'");
// Perform the transformation. processor.process(xmlSource, xslSheet, xmlResult); }
At 02:54 AM 2/2/2000 , Linda van den Brink wrote: >I've used the document() function before, but this time I don't know the >paths and filenames of the documents beforehand. These are thousands of >files in hundreds of different directories. > >I do have XML files that specify the filenames and paths of all the >documents in a specific subdirectory. Could I somehow read such a >filenames-file and call the document function for each of the files listed, >and then extract the information I want from each document? > >Maybe my best option is to use a Perl script or something similar... > >-----Original Message----- >From: Steve Tinney [mailto:stinney@xxxxxxxxxxxxx] >Sent: Tuesday, February 01, 2000 3:58 PM >To: xsl-list@xxxxxxxxxxxxxxxx >Subject: Re: multiple input files to one output file > > >Linda van den Brink wrote: >> Is it possible with XSLT to have lots of input files, and create one >output >> file listing specific data from each of the files? >> >> What are my options to achieve this? > >XSLT spec under document(). You will need to manage the actual >integration of your list of documents into the XSL script, either >manually, by use of some kind of XML control file, or with a Java >extension function. > > Steve > >-- >---------------------------------------------------------------------- >Steve Tinney Babylonian Section > * University of Pennsylvania Museum >stinney@xxxxxxxxxxxxx Phila, PA. 215-898-4047 > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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