Subject: Re: How to get the value of the node From: "Raimond Brookman" <nucleon@xxxxxxxxxx> Date: Fri, 12 May 2000 20:10:42 +0200 |
You have to take in account the fact that XML is CaSe-sensitive... So write NodeList nl = doc.getElementsByTagName("EXPIRE"); This should work a lot better... Grtz, Raimond ----- Original Message ----- From: "Cheun N Chong" <cnc99r@xxxxxxxxxxxxxxx> To: <XSL-List@xxxxxxxxxxxxxxxx> Sent: Friday, May 12, 2000 1:29 PM Subject: HELP: How to get the value of the node Hi all, Perhaps I have really repeated my question several times and I am terribly sorry about that. I am quite frustrated here. I have the following codes: =============== THE XML CODES ======================= <BOUGHTSTUFF> <STUFF> <TYPE>milk</TYPE> <EXPIRE>6 may 2000</EXPIRE> </STUFF> <STUFF> <TYPE>pork chop</TYPE> <EXPIRE>7 may 2001</EXPIRE> </STUFF> </BOUGHTSTUFF> =============== THE JAVA CODES ====================== fileinput = new FileInputStream("stuff.xml"); xmlinput = new InputSource(fileinput); // Use a DOMParser from Xerces so we get a complete DOM from the document DOMParser parser = new DOMParser(); parser.parse(xmlinput); // Get the document and the node list of the required tag name Document doc = parser.getDocument(); NodeList nl = doc.getElementsByTagName("Expire"); out.println(nl.getLength()); Node n = nl.item(0); String value = nl.item(0).getNodeValue(); out.println(value); ====================================================== I want to get the node value of Expire for milk. However when I tried that code, it print out "null" but when I change the getNodeValue() to getNodeName(), it can print out the "Expire". Is there any wrong codes. I really need your expertise. Thousand thanks. Wish you all the best. Best regards, Cheun Ngen CHONG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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