Subject: RE: counting and displaying with xsl? From: Sean Lockhart <SeanL@xxxxxxxxxxx> Date: Wed, 7 Jun 2000 14:22:01 -0700 |
The following has worked for me before: <xsl:if expr="(childNumber(this) % 5) == 1"> -----Original Message----- From: juggy@xxxxxxx [mailto:juggy@xxxxxxx] Sent: Tuesday, June 06, 2000 5:07 PM To: xsl-list@xxxxxxxxxxxxxxxx Subject: counting and displaying with xsl? Hi, Is there any way to use xsl to count the number of items in my xml? I'd like to know this so I could arrange them according to their number (e.g. have a line break every 5 items). I think of something like <xsl:if "count > 5"> ARRANGE NORMAL <xsl:if-otherwise> LINEBREAK ARRANGE NORMAL ... Juggy XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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