Sorting across Multiple branches of XML

["Chidester, Brice" <Brice.Chidester@xxxxxxxxx>]

I'm wondering if it's possible to use the <xsl:sort> tag to sort elements
that lie across multiple branches of my XML file. For instance, my XML might
look as follows:

<node_list>
   <hp>
      <hp_node>
        <node_name>aaa</node_name>
        <type>hp</type>
      </hp_node>
      <hp_node>
        <node_name>ccc</node_name>
        <type>hp</type>
      </hp_node>
   </hp>
   <sun>
      <sun_node>
        <node_name>bbb</node_name>
        <type>sun</type>
      </sun_node>
   </sun>
</node_list>

I currently have an xsl file that appears similar to this:

<xsl:stylesheet>

  <xsl:template match="node_list">
    <xsl:apply-templates>
      <xsl:sort order="descending"
              select="node_name"/>
    </xsl:apply-templates>
 </xsl:template>

 <xsl:template match="hp_node">
   <xsl:value-of
        select="node_name"/>
   <xsl:value-of
        select="type"/>
 </xsl:template>

 <xsl:template match="sun_node"> 
   <xsl:value-of
        select="node_name"/>
   <xsl:value-of
        select="type"/>
 </xsl:template>

</xsl:stylesheet>

Currently, my output appears like this:

aaa
hp
ccc
hp
bbb
sun

Is there any way to make it appear like this?:

aaa
hp
bbb
sun
ccc
hp

I'd really appreciate any suggestions anyone could offer. Thanks.

Brice Chidester


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