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Re: arbitrary sorting (Part IV)

Subject: Re: arbitrary sorting (Part IV)
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 20 Jul 2000 15:36:04 GMT
> Tricky, because there's no XPath facility to determine the position of a
> node relative to its siblings: you can only do this using <xsl:number/>, and
> you can't invoke XSLT-level operations while computing a sort key. 

but you could presumably use count(preceding-sibling::*)+1

David


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