Subject: RE: Standard XPath expression for the intersection of two node se ts (Was: RE: How can I test if an node included in a nodeset) From: Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 4 Aug 2000 10:59:05 +0200 (MET DST) |
Hi, > > This is so cool, I hope it gets into the FAQ. It certainly deserves > > documentation along with Muenchian keys and other Advanced > > Tricks. Does > > Mike get his name on it (a Kayish intersection)? [...] > > (And yes, it will go into the faq) I don't know if anybody has mentioned this before: We had already $nodes1[count(.|$nodes2)=count($nodes2)] as intersection expression. If we add a single exclamation mark $nodes1[count(.|$nodes2)!=count($nodes2)] it will become the difference of the two node-sets $nodes1 and $nodes2. Regards, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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