Subject: Re: Axis problem From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Tue, 12 Sep 2000 19:09:14 +0100 |
Juergen, >Instead of the XXXXX I tried several XPath-Expressions (parent, >ancestor, ...), but I never get the @name of the component which >properties I am processing now. The other stuff (propertyName and >specialPropertyName) works correctly. It sounds like you're on the right track. The XPath has to take you from the current node to the 'component' element, and then get the value of its 'name' attribute. The current node, within the xsl:for-each in your template, is a 'property' element, so the relevant piece of the hierarchy looks like: <component name="..."> ^^^^^^^^^^ you want to get here <properties> <property /> <-- you are here </properties> </component> You could class the 'component' element that contains the current node as the most recent 'component' ancestor of the current node: ancestor::component[1] or as the parent 'properties's parent 'component' (which is slightly better because it means even an unoptimised XSLT processor won't collect together a list of all the ancestors): parent::properties/parent::component or shorter (as the names of the parents aren't in question): parent::*/parent::* or finally in shorthand as the parent element's parent: ../.. Once you've got to the 'component' element, getting to the 'name' attribute involves the attribute axis, either as: attribute::name or, in shorthand, @name So you're looking for either: <xsl:value-of select="parent::properties/parent::component/attribute::name" /> Or, shorter: <xsl:value-of select="parent::*/parent::*/attribute::name" /> Or, shortest: <xsl:value-of select="../../@name" /> Or any combination of the above :) I hope that this helps, Jeni Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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