Subject: Re: testing an attribute value and node value From: Warren Hedley <w.hedley@xxxxxxxxxxxxxx> Date: Tue, 19 Sep 2000 11:53:45 +1200 |
Hi Russ, It appears from your stylesheet namespace that you're using an old version of IE5, so the following may not work. (Actually, I haven't had time to test it so it may not work at all.) Russ Holmes wrote: > > I want to generate HTML for each node 'F' dependent on the value of the 'n' > attribute and the value of the current node. Do you only want to produce output for certain values of @n? If not, then you should be fine with this. <xsl:template match="F"> <DIV> <xsl:if test=". = '1'"> <b> <xsl:value-of select="concat(@n, ' Works')" /> </b> </xsl:if> </DIV> </xsl:template> Note that your test expression > <xsl:when test="@n[.='100' and //F[.='1']]"> is not selecting the parent F element of the @n attribute as you may be thinking. "//F" selects all F elements in the document. If you want to test on specific values of @n as well as the contents of F being "1", then try <xsl:template match="F"> <DIV> <xsl:if test=". = '1' and @n = '100'"> ... > My other thought was to alter the XMl slightly so that it had the '1' value > as an attribute.. Hopefully, it shouldn't be necessary. Hope this helps. -- Warren Hedley Department of Engineering Science Auckland University New Zealand XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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