Subject: RE: carriage return in XML ---> <br /> in HTML - how ? From: "Jarno Elovirta" <jarno@xxxxxxxxxxxxxx> Date: Fri, 22 Sep 2000 11:45:24 +0300 |
> Any ideas someone ? How about an edited version of the solution from http://www.dpawson.freeserve.co.uk/xsl/replace.html#N25057: [c:\temp]type test.xml <?xml version="1.0"?> <Text> This is where the actual article starts. The article contains several paragraphs. Paragaraphs are separated by Carriage returns or Linefeeds, not by Tags </Text> [c:\temp]type test.xsl <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="text()"> <xsl:call-template name="break" /> </xsl:template> <xsl:template name="break"> <xsl:param name="text" select="."/> <xsl:choose> <xsl:when test="contains($text, '
')"> <xsl:value-of select="substring-before($text, '
')"/> <br/> <xsl:call-template name="break"> <xsl:with-param name="text" select="substring-after($text,'
')"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$text"/> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> [c:\temp]saxon test.xml test.xsl <?xml version="1.0" encoding="utf-8"?><Text><br/> This is where the actual article starts. The article contains<br/> several paragraphs.<br/><br/> Paragaraphs are separated by Carriage returns or Linefeeds, not by Tags<br/></Text> Cheers, Jarno - The Smiths: Meat Is Murder XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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