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Subject: RE: Forcing String Length? From: "Chris Bayes" <Chris@xxxxxxxxxxx> Date: Fri, 22 Sep 2000 14:33:45 -0400 (EST) |
Rebecca,
Try something like
<xsl:template match="something">
<xsl:call-template name="padto10">
<xsl:with-param name="string" select="text()" />
</xsl:call-template>
</xsl:template>
<xsl:template name="padto10">
<xsl:param name="string" />
<xsl:variable name="spadding" select="' '" />
<xsl:variable name="ipadding" select="'0000000000'" />
<xsl:if test="string-length(normalize-space(translate(., '1234567890', '
')))>0">
<xsl:value-of select="concat($string , substring($spadding,
string-length($string)))" />
</xsl:if>
<xsl:if test="string-length(normalize-space(translate(., '1234567890', '
')))=0">
<xsl:value-of select="concat($string , substring($ipadding,
string-length($string)))" />
</xsl:if>
</xsl:template>
Ciao Chris
XML/XSL Portal
http://www.bayes.co.uk/xml
My question for the day is this:
Is there away to force string length? For example, my output contains a
string that must contain 10 characters but the XML source is not guaranteed
to supply that number of characters.
Is there a better, shorter way than doing a long series using <xsl:choose>,
testing string-length=10, string-length=9 etc and filling in the appropriate
number of spaces (or 0's if it's a number)
My stylesheet HUGE because I have so many places where this must be done.
It's working but I've got to find ways to trim it down.
Help!
Thanks,
Rebecca
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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