RE: Variation on a Grouping Question

Subject: RE: Variation on a Grouping Question
From: Raj Muchhala <rmuchhala@xxxxxxxxxxxxxx>
Date: Mon, 25 Sep 2000 16:48:31 -0400 (EST)
Thanks Gary for your response.  Unfortunately your first solution: 

--> <xsl:apply-templates select="z:row[@job_number = $job
-->    and generate-id(.) = generate-id(key('by_city', @city)[@job_number =
--> $job])]" >

works only for a small xml file.  Running it against the full file with over

9K records froze the client...

I did, however, come up with a different method that runs alot faster:

Define the key like this:

--> <xsl:key name="group_by_city" match="/xml/rs:data/z:row"
use="concat(@job_number, '::', @city)" />

And use an 'apply-templates select' like this:

--> <xsl:apply-templates select="*[@city and
generate-id(.)=generate-id(key('group_by_city', concat(@job_number, '::',
@city))) and @job_number = $job]"> 



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