Subject: RE: Selecting all descendants with no child nodes From: "John Dreystadt" <jdreysta@xxxxxxxxxxxxx> Date: Tue, 3 Oct 2000 16:32:32 -0400 |
Since an empty nodelist evaluates to false, "//*[*]" works just as well and should run faster. I assume you wanted a faster version (if you had a different reason for wanting an alternative, speak up). Yours requires some extra operations to compute than the option above. But I suspect that performance will not matter much. John Dreystadt > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Taras Tielkes > Sent: Tuesday, October 03, 2000 4:25 PM > To: xsl-list@xxxxxxxxxxxxxxxx > Subject: Selecting all descendants with no child nodes > > > Hi, > (I hope people don't mind a beginner xpath question now and then) > > I'm using the XPath expression "//*[count(*)=0]" to locate > all "endpoint" > nodes. > > Is there any other way to achieve this, an alternative syntax? > > Thanks in advance, > Taras > > > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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