Subject: Re: indent XML doc based on spaces? From: mnaughto@xxxxxxxxxxx Date: Thu, 5 Oct 2000 09:54:44 +0100 |
Hi Joshua, I didn't check your algorithm, but here is a stylesheet I use to display colour-coded and indented XML, in case it provides useful ideas. Having set the FONT to Courier, it achieves the indenting at each level with this HTML technique: <DIV STYLE="margin-left:1em;"> This version uses the obsolete IE5 XSL namespace. If this is useful, I can't claim the credit - I didn't write this stylesheet... Anyway, here's the code: <?xml version="1.0"?> <!-- Generic stylesheet for viewing XML --> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> <!-- This template will always be executed, even if this stylesheet is not run on the document root --> <xsl:template> <DIV STYLE="font-family:Courier; font-size:10pt; margin-bottom:2em"> <!-- Scoped templates are used so they don't interfere with the "kick-off" template. --> <xsl:apply-templates select="."> <xsl:template><xsl:apply-templates/></xsl:template> <xsl:template match="*"> <DIV STYLE="margin-left:1em; color:gray"> <<xsl:node-name/><xsl:apply-templates select="@*"/>/> </DIV> </xsl:template> <xsl:template match="*[node()]"> <DIV STYLE="margin-left:1em"> <SPAN STYLE="color:gray"><<xsl:node-name/><xsl:apply-templates select="@*"/>></SPAN><xsl:apply-templates select="node()"/><SPAN STYLE="color:gray"></<xsl:node-name/>></SPAN> </DIV> </xsl:template> <xsl:template match="@*"> <SPAN STYLE="color:navy"> <xsl:node-name/>="<SPAN STYLE="color:black"><xsl:value-of /></SPAN>"</SPAN> </xsl:template> <xsl:template match="pi()"> <DIV STYLE="margin-left:1em; color:maroon"><?<xsl:node-name/><xsl:apply-templates select="@*"/>?></DIV> </xsl:template> <xsl:template match="cdata()"><pre><![CDATA[<xsl:value-of />]]></pre></xsl:template> <xsl:template match="textNode()"><xsl:value-of /></xsl:template> </xsl:apply-templates> </DIV> </xsl:template> </xsl:stylesheet> Thanks, Martin XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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