Subject: RE: Alternate bg colors for table and address summaries From: "Paul Essex" <paul@xxxxxxxxxxxxxx> Date: Wed, 1 Nov 2000 18:23:23 -0400 (EST) |
>Date: Wed, 25 Oct 2000 15:51:13 EDT >From: "Robert Saylor" <rrsaylor@xxxxxxxxxxx> >Subject: Alternate bg colors for table and address summaries >Here is the dilemma, >I want to have one summary return with a grey background and the other >summary with a white background. >Ive tried the position function and have had no luck perhaps its me as im >new at this? I think you're on the right track with the position function, although I didn't see that code in the stylesheet you included with your message. Take a look at page 367 in Michael Kay's XSLT book. The very last entry in the Examples table shows this method of determining whether a node's position is even: item[position() mod 2 = 0] Use this in an xsl:when test something like this: <xsl:choose> <xsl:when test="Summary[position() mod 2 = 0]> <xsl:call-template name="bgcolorgrey"/> </xsl:when> <xsl:otherwise> <xsl:call-template name="bgcolorwhite"/> </xsl:otherwise> </xsl:choose> You can then create two named templates to create the table rows, one implementing a gray background and the other implementing a white background. I thought about a simpler way to do this, which would be to simply do the test and set a variable value to the desired color, then use the variable for the 'bgcolor' attribute of the <tr> tag. I'm not sure if that would work, though. I'd be concerned if the variable would stay in scope after you exit the xsl:choose, and I'm also not sure if it would be recreated for each node processed in the xsl:for-each (although I think it would). Perhaps someone more experienced than I am can comment on that. Hope that helps! Paul Essex Software Developer Bridgeway Software, Inc. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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