Subject: Re: Var references in "match" attribute of xsl:template? From: dkarr@xxxxxxxx (David M. Karr) Date: 10 Nov 2000 12:05:37 -0800 |
>>>>> "Jeni" == Jeni Tennison <mail@xxxxxxxxxxxxxxxx> writes: Jeni> David, >> I vaguely remember I've read that the value of the "match" attribute >> of "xsl:template" cannot reference a variable in any way. If that's >> true, then I have to duplicate the domain class name in the >> "domainClass" setting, and in the top-level "xsl:template" tag. It >> would be nice if I could define the domain class in a single place, >> and reference it in all the places it is used. Is there any way to do >> this? Jeni> However, I note from your description that: >> The name of the root tag element is exactly the same as the domain >> class. Jeni> By 'root tag element' I guess you mean the document element: the Jeni> element at the very top of the document tree. If that's the case, Jeni> then you can always get the name of that element through the XPath: Jeni> name(/*) [or local-name(/*) if you're using namespaces] Jeni> i.e. the name of the element that is a child of the root node. You Jeni> *can* use this expression within the match pattern of a template. Jeni> You can also match on the document element (the element representing Jeni> your domain class) with the match pattern: Jeni> /* Thanks. Based on this advice, I found I can avoid encoding the name of the domain class in the XSL completely, by using a top-level match spec of "/*" and in the template set my "domainClass" variable from "name()". -- =============================================================================== David M. Karr ; dkarr@xxxxxxxx ; w:(425)487-8312 ; TCSI & Best Consulting Software Engineer ; Unix/Java/C++/X ; BrainBench CJ12P (#12004) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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