Re: how to replace line-feeds with space?

Subject: Re: how to replace line-feeds with space?
From: Mike Brown <mike@xxxxxxxx>
Date: Tue, 14 Nov 2000 22:41:56 -0700 (MST)
Chad Small wrote:
> I found some info on dpawson's basic trouble-shooting under the Replace
> link, but can't seem to make the transformation work.

Actually, you're doing way too much work. If you're replacing a single
character with a single character, all you need is the XPath function

   <xsl:template match="TITLE/text()">
     <xsl:value-of select="translate(.,'&#10;',' ')"/>

Using tail recursion and substrings is only necessary if you're 
doing substring replacement, or replacing characters with elements.

   - Mike
Mike J. Brown, software engineer at         My XML/XSL resources: in Denver, Colorado, USA 

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