Subject: "Grammar not found" error when trying to load XSL Namespace From: "Flynn, Jim" <JFlynn@xxxxxxxxxx> Date: Thu, 30 Nov 2000 15:59:19 -0500 |
I am trying to run one of the examples in Brett McLaughlin's "Java and XML" book. Basically, I am attempting to use the xalan XSLT processor to transform a document into html. When I try to process the XML document, I get the following error from the Xalan processor: java org.apache.xalan.xslt.Process -VALIDATE -IN contents.xml -XSL ./XSL/JavaXML_book.html.xsl ========= Parsing file:/usr/data/dsk1/jflynn/java-xml/XSL/JavaXML.html.xsl ========== http://www.w3.org/1999/XSL/Transform grammar not found Parser error: Element type "xsl:stylesheet" must be declared. Parser error: Attribute "version" must be declared for element type "xsl:stylesh eet". Parser error: Element type "xsl:template" must be declared. Parser error: Attribute "match" must be declared for element type "xsl:template" . Parser error: Element type "html" must be declared. Parser error: Element type "head" must be declared. Parser error: Element type "title" must be declared. Parser error: Element type "xsl:value-of" must be declared. Parser error: Attribute "select" must be declared for element type "xsl:value-of ". Parser error: Element type "body" must be declared. Parser error: Element type "xsl:apply-templates" must be declared. etc. Here is the first portion of the XSL file: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform/" xmlns:JavaXML="http://www.oreilly.com/catalog/javaxml/" > I can reach the namespace docuement directly via netscape from the same machine, so I know it's not a connectivity problem. Also, it does appear that the document is partially translated. Anyone have any thoughts? TIA. -- Jim Flynn Software Dev Mgr Engage Inc 978-684-7704 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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