Re: [xsl] Implementing simple XLinks using XSL

[Eric van der Vlist <vdv@xxxxxxxxxxxx>]

Adam Van Den Hoven wrote:
> 
> But it doesn't seem to work.

When the XSLT processors will support XML fragments identifiers, ie
XPointers, you will be able to write:

<xsl:copy-of select="document(@xlink:href)" />

In the meantime, the source of your problem is probably that the id()
XPath function is always selecting a node from the current document and
you need to change of document before using it.

The following sheet does what you expect (at least with XT):

<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xlink="http://www.w3.org/1999/xlink/namespace/";>
  <xsl:template match="* | @* ">
    <xsl:copy>
      <xsl:apply-templates select="@* | *"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="*[@xlink:show='embed'][@xlink:actuate='onLoad']">
  	<xsl:apply-templates
select="document(substring-before(@xlink:href,'#'))" mode="include">
	<xsl:with-param name="id" select="substring-after(@xlink:href, '#')"/>
	</xsl:apply-templates>
  </xsl:template>
  
  <xsl:template match="/" mode="include">
  	<xsl:param name="id"/>
	<xsl:copy-of select="id($id)" /> 
  </xsl:template>
  
</xsl:stylesheet>

Hope this helps.

Eric
-- 
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Eric van der Vlist       Dyomedea                    http://dyomedea.com
http://xmlfr.org         http://4xt.org              http://ducotede.com
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