[xsl] How to select distinct combined element values

["Albert Tsun" <albert.tsun@xxxxxxxxxxxx>]

Dear All,

I got a problem in getting distinct element group values.

XML source:
+++++++++++
<match>
     <date>1-11-2000</date>
     <team>Brazil</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>2-11-2000</date>
     <team>Brazil</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Brazil</team>
     <group>B</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Argentina</team>
     <group>A</group>
     <score>1</score>
</match>
<match>
     <date>1-11-2000</date>
     <team>Argentina</team>
     <group>A</group>
     <score>1</score>
</match>

 for distinct team :
In XSL, I can use
     <xsl:variable name="teams" select = "//team[not(.=preceding::team)]"/>
to get
     Brazil
     Argentina

However, if I want to get distinct team, group, that is
     Brazil A
     Brazil B
     Argentina A

How can I do it ? would Mike give me some suggestion ?

TIA




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