Re: [xsl] using xsl:copy

[Frank Hess <hess.frank@xxxxxx>]

Use:

<xsl:template match="/catalog/item">
        <xsl:apply-templates select="description"/>
</xsl:template>

<xsl:template match="description">
        <xsl:copy-of select="."/>
</xsl:template>


At 11:59 23.01.01 -0500, you wrote:

> If I have an xml structure like this:
>
> <catalog>
>   <item>
>        <description><b>A nice shoe</b></description>
>   </item>
> </catalog>
>
> and my xsl looks like this:
>
> <xsl:template match="/catalog/item">
>         <xsl:copy-of select="description"/>
> </xsl:template>
>
>
> my HTML output is:
> <description><b>A nice shoe</b></description>
>
>
> How can I output the html without the <description> tags? I wish to preserve
> the <b> tags which may or may not be there.
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list